Q122 Jan 2025 · Shift 1MCQ
An amount of ice of mass $10^{-3}$ kg and temperature $-10^\circ$C is transformed to vapour of temperature $110^\circ$C by applying heat. The total amount of work required for this conversion is, (Take, specific heat of ice $= 2100\ \mathrm{Jkg^{-1}K^{-1}}$, specific heat of water $= 4180\ \mathrm{Jkg^{-1}K^{-1}}$, specific heat of steam $= 1920\ \mathrm{Jkg^{-1}K^{-1}}$, Latent heat of ice $= 3.35\times10^{5}\ \mathrm{Jkg^{-1}}$ and Latent heat of steam $= 2.25\times10^{6}\ \mathrm{Jkg^{-1}}$)
- A3043 J
- B3024 J
- C3003 J
- D3022 J




